Continuity of a Function Ina Interval - Search Videos

$Q) If 𝑓(𝑥)={((1−sin^3 𝑥)/(3cos^2 𝑥), for 𝑥≠𝜋/2 𝑘, for 𝑥=𝜋/2) is continuous at 𝑥=𝜋/2, t$

Q) If 𝑓(𝑥)={((1−sin^3 𝑥)/(3cos^2 𝑥), for 𝑥≠𝜋/2 𝑘, for 𝑥=𝜋/2) is continuous at 𝑥=𝜋/2, t

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Q) Evaluate sin[cos^(−1) cos(7𝜋/6)] #shivangmathsacademy #cbsemaths #class12maths #maths

Q) Evaluate sin[cos^(−1) cos(7𝜋/6)] #shivangmathsacademy #cbsemaths #class12maths #maths

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Q) Check whether function f(x) defined as f(𝑥)={((|𝑥−3|)/(2(𝑥−3)), 𝑥=3 (𝑥−6)/6,𝑥≥3) Is

Q) Check whether function f(x) defined as f(𝑥)={((|𝑥−3|)/(2(𝑥−3)), 𝑥=3 (𝑥−6)/6,𝑥≥3) Is

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$Q) The value of 𝑘 for which the function 𝑓(𝑥)={(𝑥^2 sin 1/𝑥, 𝑥≠0 𝑘(𝑥+1), 𝑥=0) is a continuo$

Q) The value of 𝑘 for which the function 𝑓(𝑥)={(𝑥^2 sin 1/𝑥, 𝑥≠0 𝑘(𝑥+1), 𝑥=0) is a continuo

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JThe number of points of discontinuity f(x) = {(|𝐱|+𝟑, 𝐢𝐟 𝐱≤−𝟑 −𝟐𝐱, 𝐢𝐟 −𝟑=𝐱=𝟑 𝟔𝐱+𝟐,

JThe number of points of discontinuity f(x) = {(|𝐱|+𝟑, 𝐢𝐟 𝐱≤−𝟑 −𝟐𝐱, 𝐢𝐟 −𝟑=𝐱=𝟑 𝟔𝐱+𝟐,

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$Find the values of 𝛌 if the function 𝐟(𝐱)={((〖𝐬𝐢𝐧^𝟐 𝛌𝐱)/𝐱^𝟐 , 𝐢𝐟 𝐱≠𝟎 𝟏, 𝐢𝐟 𝐱=𝟎)$

Find the values of 𝛌 if the function 𝐟(𝐱)={((〖𝐬𝐢𝐧^𝟐 𝛌𝐱)/𝐱^𝟐 , 𝐢𝐟 𝐱≠𝟎 𝟏, 𝐢𝐟 𝐱=𝟎)

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$Find the value of k for which the function 𝐟(𝐱)={((𝟏−𝐜𝐨𝐬𝐱)/(𝟐𝐱^𝟐 ), 𝐢𝐟 𝐱≠𝟎 𝐤, 𝐢𝐟$

Find the value of k for which the function 𝐟(𝐱)={((𝟏−𝐜𝐨𝐬𝐱)/(𝟐𝐱^𝟐 ), 𝐢𝐟 𝐱≠𝟎 𝐤, 𝐢𝐟

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Q) If 𝑓(𝑥)={(sin𝑥/𝑥+cos𝑥, 𝑥≠0 𝑘, 𝑥=0) is continuous at 𝑥=0, then the value of 𝑘 is :

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Q) If 𝑠𝑖𝑛 𝑐𝑜𝑡^(−1) (𝑥+1)]=𝑐𝑜𝑠(tan^(−1) 𝑥), 𝑡ℎ𝑒𝑛 𝑓𝑖𝑛𝑑 𝑥.#class12maths #shivang

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Q) Simplify : cot^(−1) √((1+cos2𝑥)/(1−cos2𝑥)),𝑥∈(0,𝜋/2).#maths #cbsemaths #class12 #cbse2026

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Q) The function 𝑓 defined by 𝑓(𝑥)={ (𝑥,f 𝑥≤1 5, if 𝑥= 1 is not continuous at(A) x=0(B) 𝑥

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The simplest form of tan^(−1) [(√(1+x)−√(1−x))/(√(1+x)+√(1−x))] is (a π/4−x/ #cbsemaths #maths

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If a function defined by 𝑓(𝑥)={(𝑘𝑥+1, 𝑥≤𝜋 cos𝑥 ,𝑥=𝜋) is continuous at 𝑥=𝜋, then the val

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Q) Find the value of 𝑘, so that 𝑓(𝑥)={(𝑘cos𝑥/(𝜋−2𝑥), if 𝑥≠𝜋/2@3, if 𝑥=𝜋/2) is continu

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Q) If sin^(−1) 𝑥 + pie =3𝑦, thenCBSE Class 12 Maths PYQ 2026 | Continuity of Piecewise Function

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Q) Express 𝐭𝐚𝐧^(−𝟏) (𝐜𝐨𝐬𝐱/(𝟏−𝐬𝐢𝐧𝐱)), (−𝟑𝛑)/𝟐=𝐱=𝛑/𝟐 in the simplest form.#class12

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Q) If 𝑓(𝑥)={ ((𝑥^2−4𝑥−5)/(𝑥+1), 𝑥≠−1 𝑘,&𝑥=−1 is continuous at 𝑥=−1, then the value of 𝑘 i

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Q) If 𝑓(𝑥)={(3𝑥−2, 0≤𝑥≤1 2𝑥^2+𝑎𝑥, 1≤𝑥≤2) is continuous for 𝑥∈(0,2), then a is equal to

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Find k so that 𝑓(𝑥)={((𝑥^2−2𝑥−3)/(𝑥+1), 𝑥≠−1 𝑘, 𝑥=−1) is continuous at x=−1.#cbse2027 #maths

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Q) Simplify: 𝐜𝐨𝐬^(−𝟏) 𝐱+𝐜𝐨𝐬^(−𝟏) [𝐱/𝟐+√(𝟑−𝟑𝐱^𝟐 )/𝟐]; 𝟏/𝟐≤𝐱≤𝟏 #cbsemaths #maths

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